5=x^2+7x

Solution for 5=x^2+7x equation:

5=x^2+7x

We move all terms to the left:

5-(x^2+7x)=0

We get rid of parentheses

-x^2-7x+5=0

We add all the numbers together, and all the variables

-1x^2-7x+5=0

a = -1; b = -7; c = +5;
Δ = b2-4ac
Δ = -72-4·(-1)·5
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{69}}{2*-1}=\frac{7-\sqrt{69}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{69}}{2*-1}=\frac{7+\sqrt{69}}{-2}
$